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How many four-digit odd numbers can be formed from the digits {0, 1, 2, 3, 4, 5, 6, 7, 8} without repetition?

Answer and explanation

Correct answer: 1176 numbers

The units digit must be one of 1, 3, 5, or 7, giving 4 choices. After that, the thousands digit has 7 nonzero choices left. The hundreds and tens digits then have 7 and 6 choices, respectively. Thus, 4 × 7 × 7 × 6 = 1176 numbers.

Related tags

PermutationsDigit CountingFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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