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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingMedium
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An auditorium has (5) blocks each block has (6) rows and each row has (8) seats. If the program has (2) shifts how many ways are there to choose one seat-shift?

Answer and explanation

Correct answer: 480

To specify one seat-shift, choose a block, a row in that block, a seat in that row, and a shift. By the fundamental principle of counting, the total number of ways is \(5 \times 6 \times 8 \times 2=480\). Option 240 misses the 2 choices of shift. Exam tip: Multiply the numbers of choices at successive independent stages.

Related tags

Fundamental Counting PrinciplePermutations And CombinationsAuditorium SeatingMultiplication RuleClass 11 MathematicsFundamental Principle Of CountingMathematicsClass 11 Mcq
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