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Using the digits (1,2,3,4,5,6,7,8,9) without repetition (2)-digit numbers are formed. The number must be greater than (70). How many numbers are possible?

Answer and explanation

Correct answer: (24) numbers

Direct answer: option C, 24 numbers. A two-digit number has a tens digit and a units digit. To be greater than 70, its tens digit must be 7, 8, or 9. If the tens digit is 7, the units digit can be any of the other eight digits: 1,2,3,4,5,6,8,9. The same eight choices are available when the tens digit is 8 or 9, because repetition is forbidden. Therefore the count is 3×8=24. Option A, 18, undercounts the available units choices. Option B, 21, also does not use the full 3×8 count. Option C, 24, correctly counts all choices without repetition. Option D, 27, would incorrectly allow nine units choices for each tens digit, including repetition of the selected tens digit. Note that 70 itself cannot be formed because digit 0 is not supplied, and all numbers beginning with 7, 8, or 9 are greater than 70.

Related tags

Counting-Principle Medium Class11Fundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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