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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingMedium
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Using the letters A, B, C, D, E, F, G, and H, form 3-letter codes without repetition. The first letter cannot be A or B. How many codes are possible?

Answer and explanation

Correct answer: 252 codes

There are 6 choices for the first letter, since A and B are excluded. With no repetition, there are then 7 choices for the second letter and 6 for the third. The total is 6 × 7 × 6 = 252 codes.

Related tags

Counting PrinciplePermutationsFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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