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A code consists of 2 distinct digits followed by 2 distinct letters. The available digits are 0, 1, 2, 3, and 4, and the available letters are P, Q, R, and S. How many codes are possible?

Answer and explanation

Correct answer: 240 codes

The two digit positions can be filled in 5 × 4 ways, since the digits must be distinct. The two letter positions can be filled in 4 × 3 ways. Therefore, the total is (5 × 4) × (4 × 3) = 240 codes.

Related tags

Counting PrinciplePermutations And CombinationsClass 11Fundamental Principle Of CountingMathematicsClass 11 Mcq

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