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A 4-place PIN uses the digits 0, 1, 2, 3, and 4. The digits in the first two places must be different, while repetition is allowed in the remaining places. How many PINs are possible?

Answer and explanation

Correct answer: 500 PINs

The first place has 5 choices and the second has 4 choices because its digit must differ from the first. Each of the last two places has 5 choices, since repetition is allowed there. Thus, the total is 5 × 4 × 5 × 5 = 500 PINs.

Related tags

Counting PrinciplePermutations And CombinationsClass 11Fundamental Principle Of CountingMathematicsClass 11 Mcq

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