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A 3-digit number is formed with its hundreds digit chosen from 2, 4, or 6, its units digit chosen from 1, 3, 5, or 7, and its tens digit chosen from 0 to 9. How many such numbers are possible?

Answer and explanation

Correct answer: 120 numbers

There are 3 choices for the hundreds digit, 10 for the tens digit, and 4 for the units digit. These choices are independent, so the total is 3 × 10 × 4 = 120.

Related tags

Counting PrincipleNumber FormationFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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