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A 4-digit number is formed with its first two digits chosen from 1, 2, and 3, and its last two digits chosen from 7, 8, and 9. No digit may be repeated. How many numbers are possible?

Answer and explanation

Correct answer: 36 numbers

The first two positions can be filled in 3 × 2 ways, and the last two positions also in 3 × 2 ways. The digit sets for these two pairs are disjoint, so the total is 3 × 2 × 3 × 2 = 36 numbers.

Related tags

Counting PrincipleRestricted CountingFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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