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A 3-digit number is formed using distinct digits from 2, 3, 4, 5, 6, 7, and 8. The number must be greater than 500. How many such numbers are possible?

Answer and explanation

Correct answer: 120 numbers

The hundreds digit must be 5, 6, 7, or 8, giving 4 choices. After choosing it, there are 6 choices for the tens digit and 5 for the units digit. Thus, 4 × 6 × 5 = 120 numbers are possible.

Related tags

Counting PrincipleRestricted CountingFundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq

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