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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingMedium
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Using the letters A, B, C, D, E, and F without repetition, form 3-letter codes. The first letter cannot be A or B. How many codes are possible?

Answer and explanation

Correct answer: 80 codes

The first letter has 4 choices: C, D, E, or F. After choosing it, 5 letters remain for the second place and 4 for the third. Therefore, 4 × 5 × 4 = 80 codes are possible.

Related tags

Counting PrinciplePermutationsClass 11Fundamental Principle Of CountingPermutations And CombinationsMathematicsClass 11 Mcq
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