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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingMedium
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A shopkeeper has 4 types of packets and 6 types of labels. One packet and one label are to be chosen, but 2 distinct packet–label pairs are not allowed. How many valid choices are possible?

Answer and explanation

Correct answer: 22 options

There are 4 × 6 = 24 possible packet–label pairs before restrictions. Removing the 2 distinct pairs that are not allowed leaves 24 − 2 = 22 valid choices.

Related tags

Permutations And CombinationsFundamental Principle Of CountingMathematicsClass 11 Mcq
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