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In a (4)-place code the first place has (3) letter choices, the second has (4) digit choices, the third has (2) symbol choices and the fourth has (5) color choices. How many codes are possible?

Answer and explanation

Correct answer: (120) codes

The governing rule is the multiplication principle for independent successive choices. A complete code contains four positions, and a choice must be made at every position. The first position can be filled in 3 ways, the second in 4 ways, the third in 2 ways, and the fourth in 5 ways. Since each choice at one position may be combined with every permitted choice at the other positions, the number of complete codes is 3 × 4 × 2 × 5. Computing step by step gives 3 × 4 = 12 and 2 × 5 = 10, so the product is 12 × 10 = 120. Therefore option C is correct. Addition would count isolated choices rather than complete four-place codes.

Related tags

Permutations And CombinationsFundamental Principle Of CountingCode FormationMathematicsClass 11 Mcq

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