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Subjects
Class 11MathematicsPermutations and CombinationsFundamental principle of countingEasy
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An exam code has (2) digits followed by (1) letter. Digits are from (0) to (9) and (5) letters are given. With repetition allowed, how many codes can be formed?

Answer and explanation

Correct answer: (500)

The two digit positions have (10) and (10) choices, and the letter has (5) choices. Total ways are (10\times10\times5=500).

Related tags

Permutations And CombinationsCounting PrincipleCodesFundamental Principle Of CountingMathematicsClass 11 Mcq
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