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A student chooses one item each from (2) bags, (5) water bottles, and (3) lunch boxes. How many total ways are possible?

Answer and explanation

Correct answer: 30

There are 2 choices for the bag. For each bag, there are 5 choices for the water bottle, and for every such pair, there are 3 choices for the lunch box. Therefore, by the fundamental principle of counting, the total number of ways is \(2\times5\times3=30\). The value 10 is only \(2\times5\) and ignores the lunch-box choices. Exam tip: When one item is chosen from each independent category, multiply the numbers of choices.

Related tags

Fundamental Principle Of CountingMultiplication RulePermutations And CombinationsClass 11 MathematicsCounting MethodsMathematicsClass 11 Mcq

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