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What is the simplified value of \( \frac{8!\cdot11!}{10!\cdot7!} \)?

Answer and explanation

Correct answer: 88

Substitute \(8!=8\cdot7!\) and \(11!=11\cdot10!\):
\(\frac{8!\cdot11!}{10!\cdot7!}=\frac{(8\cdot7!)(11\cdot10!)}{10!\cdot7!}=8\cdot11=88\). Therefore, option C is correct. After cancelling \(10!\) and \(7!\), only 8 and 11 remain; 80 is not their product. Exam tip: in factorial fractions, cancel common factorial terms before expanding or multiplying.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsClass 11 MathematicsAlgebraic SimplificationMathematicsClass 11 Mcq

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