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What is the value of \( \frac{12!}{6!\cdot6!}\times\frac{3}{11} \)?

Answer and explanation

Correct answer: 252

\(\frac{12!}{6!\cdot6!}=\binom{12}{6}=924\). Therefore, \(924\times\frac{3}{11}=84\times3=252\). Hence, 252 is correct. Getting 264 would require incorrectly taking \(924\div11\) as 88, whereas it equals 84. Exam tip: first recognise such factorial ratios as \(\binom{n}{r}\), then simplify.

Related tags

Factorial NotationBinomial CoefficientPermutations And CombinationsCombinatoricsClass 11 MathematicsMathematicsClass 11 Mcq

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