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If ( \frac{(n+6)!}{(n+3)!}-\frac{(n+5)!}{(n+2)!}=546 ), what is the value of (n)?यदि ( \frac{(n+6)!}{(n+3)!}-\frac{(n+5)!}{(n+2)!}=546 ), तो (n) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8)(8)
The simplified form is (3(n+5)(n+4)). Since (3\cdot13\cdot12=468) is wrong and (3\cdot14\cdot13=546), (n=8).सरल रूप (3(n+5)(n+4)) है। (3\cdot13\cdot12=468) नहीं, सही (3\cdot14\cdot13=546) से (n=8) मिलता है।
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