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What is \( \frac{(4n+1)!}{(4n-1)!} \) equal to?

Answer and explanation

Correct answer: \((4n+1)(4n)\)

Expanding the numerator up to the factorial in the denominator gives \((4n+1)!=(4n+1)(4n)(4n-1)!\). The factor \((4n-1)!\) then cancels, leaving \((4n+1)(4n)\). Option D incorrectly retains the factor \((4n-1)\). Exam tip: In a factorial quotient, expand the larger factorial only as far as the denominator factorial.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsAlgebraic ExpressionsClass 11 MathematicsMathematicsClass 11 Mcq

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