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What is the value of \( \frac{23!}{21!\cdot2!}+\frac{22!}{20!\cdot2!} \)?

Answer and explanation

Correct answer: 484

Since \(23!=23\times22\times21!\), the first term is \(\frac{23\times22}{2!}=253\). Similarly, \(22!=22\times21\times20!\), so the second term is \(\frac{22\times21}{2!}=231\). Hence, the value is \(253+231=484\). Option 474 is incorrect and can result from an error in multiplication or addition. Exam tip: In factorial fractions, cancel the common factorial first and then multiply the remaining factors.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsBinomial CoefficientsClass 11 MathematicsMathematicsClass 11 Mcq

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