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What is the simplified value of \( \frac{18!}{14!\cdot4!}\div\frac{17!}{13!\cdot4!} \)?

Answer and explanation

Correct answer: \(\frac{9}{7}\)

In the given expression, \(4!\) cancels out. Next, \(\frac{18!}{17!}=18\) and \(\frac{13!}{14!}=\frac{1}{14}\). Hence, the value is \(18\times\frac{1}{14}=\frac{9}{7}\). \(\frac{153}{119}\) is not fully simplified; it also reduces to \(\frac{9}{7}\). Exam tip: In factorial divisions, cancel common factorial terms first and then simplify consecutive factors.

Related tags

Factorial NotationPermutations And CombinationsFactorial SimplificationBinomial CoefficientsClass 11 MathematicsMathematicsClass 11 Mcq

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