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What is the value of \( \frac{9!+2\cdot8!}{7!} \)?\( \frac{9!+2\cdot8!}{7!} \) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 8888
Use \(9!=9\cdot8\cdot7!\) and \(8!=8\cdot7!\). Hence, \(\frac{9!+2\cdot8!}{7!}=9\cdot8+2\cdot8=72+16=88\). Option 84 results from an incorrect simplification of the \(2\cdot8!\) term. Exam tip: rewrite each factorial in terms of the denominator factorial before cancelling.\(9!=9\cdot8\cdot7!\) तथा \(8!=8\cdot7!\)। इसलिए \(\frac{9!+2\cdot8!}{7!}=9\cdot8+2\cdot8=72+16=88\)। विकल्प 84 में \(2\cdot8!\) वाले पद का सही सरलीकरण नहीं होता। परीक्षा टिप: भिन्न में फैक्टोरियल पदों को हर के फैक्टोरियल के गुणज के रूप में लिखकर \(7!\) काटें।
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