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What is the value of \( \frac{10!}{5!\cdot5!}\times\frac{5}{9} \)?

Answer and explanation

Correct answer: 140

\(\frac{10!}{5!\cdot5!}=\binom{10}{5}=252\). Therefore, \(252\times\frac{5}{9}=28\times5=140\). Hence, 140 is the correct answer. Although 150 may appear close, dividing 252 by 9 gives exactly 28, so the result is 140. Exam tip: Recognising factorial ratios as combinations such as \(\binom{n}{r}\) makes calculations quicker.

Related tags

Factorial NotationBinomial CoefficientPermutations And CombinationsMathematics Class 11CombinatoricsMathematicsClass 11 Mcq

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