0 reads0 ratings0 helpful
What is the value of \( \frac{12!}{8!\cdot4!}+\frac{12!}{9!\cdot3!} \)?\( \frac{12!}{8!\cdot4!}+\frac{12!}{9!\cdot3!} \) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 715715
The first term is \(\frac{12!}{8!4!}=\binom{12}{4}=495\), and the second term is \(\frac{12!}{9!3!}=\binom{12}{3}=220\). Therefore, their sum is \(495+220=715\). A nearby value such as 705 can result from an addition error. Exam tip: recognising such expressions as \(\binom{n}{r}\) makes calculation faster.पहला पद \(\frac{12!}{8!4!}=\binom{12}{4}=495\) है और दूसरा पद \(\frac{12!}{9!3!}=\binom{12}{3}=220\) है। अतः योग \(495+220=715\) होगा। 705 जैसी निकट संख्या जोड़ में त्रुटि से आ सकती है। परीक्षा टिप: ऐसे व्यंजकों को \(\binom{n}{r}\) के रूप में पहचानने से गणना तेज होती है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
