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If ( \frac{(2n+1)!}{(2n-1)!}=272 ), what is the value of (n)?यदि ( \frac{(2n+1)!}{(2n-1)!}=272 ), तो (n) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8)(8)
It is ((2n+1)(2n)=272), and (17\cdot16=272), so (2n=16) and (n=8). Identify the consecutive factors first.यह ((2n+1)(2n)=272) है और (17\cdot16=272), इसलिए (2n=16) और (n=8)। पहले लगातार गुणकों को पहचानें।
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