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What is the value of \( \frac{9!}{6!\cdot2!} \)?

Answer and explanation

Correct answer: 252

Since \(9!=9\times8\times7\times6!\), \(\frac{9!}{6!\cdot2!}=\frac{9\times8\times7}{2}=252\). Therefore, 252 is correct. The value 336 is a common error obtained by not dividing by \(2!\). Exam tip: In factorial fractions, cancel the common factorial term first and then multiply the remaining factors.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsClass 11 MathematicsMathematicsClass 11 Mcq

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