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If ( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!}=216 ), what is the value of (n)?यदि ( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!}=216 ), तो (n) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (6)(6)
The simplified form is (3(n+1)(n+2)), so ((n+1)(n+2)=72) and (n=7); the correct option is (7). First simplify and then match options.सरल रूप (3(n+1)(n+2)) है, इसलिए ((n+1)(n+2)=72) और (n=7) होगा; सही विकल्प (7) है। पहले रूप निकालकर विकल्प मिलाएं।
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