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Class 11 Mathematics Permutations and Combinations Factorial notationHard

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If ( \frac{(n+4)!}{(n+1)!}=990 ), what is the value of (n)?

Answer and explanation

Correct answer: (8)

((n+4)(n+3)(n+2)=990), and (11\cdot10\cdot9=990), so (n=7). Match the three consecutive factors carefully.

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Permutations Combinations Factorial Hard Factorial Notation Permutations And Combinations Mathematics Class 11 Mcq

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