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What is the value of \( \frac{18!}{16!\cdot2!} \times \frac{2}{17} \)?

Answer and explanation

Correct answer: 18

Since \(18! = 18\times17\times16!\), we get \(\frac{18!}{16!\cdot2!}=\frac{18\times17}{2}=153\). Therefore, \(153\times\frac{2}{17}=18\). Hence, the correct answer is 18. Getting 17 is a common error caused by not simplifying the final factor \(\frac{2}{17}\) correctly. Exam tip: In factorial questions, expand the larger factorial only up to the smaller factorial and cancel common factors first.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsClass 11 MathematicsMathematicsClass 11 Mcq

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