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Find the value of 15! / (13! × 2).

Answer and explanation

Correct answer: 105

Use the factorial identity 15!=15×14×13!. Substituting this form into the expression gives 15!/(13!×2)=(15×14×13!)/(13!×2). The common factor 13! cancels, leaving (15×14)/2=210/2=105. Therefore option A is correct. The expression is also equal to the combination 15C2, although recognizing that interpretation is optional. Option B is the product 15×14 before division by 2, so it ignores an essential denominator factor. Option C is unrelated to the required cancellation, and option D may result from an incorrect arithmetic operation. The denominator 2 remains after 13! is cancelled and must not be discarded.

Related tags

Factorial NotationAlgebraic CancellationBinomial CoefficientClass 11Permutations And CombinationsMathematicsClass 11 Mcq

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