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What is the value of ( \frac{12!}{10!\cdot3!} )?

Answer and explanation

Correct answer: (22)

The direct answer is A, 22. Expand only the part needed for cancellation: \(12!=12\times11\times10!\), and \(3!=3\times2\times1=6\). Thus \(\frac{12!}{10!\cdot3!}=\frac{12\times11\times10!}{10!\times6}=\frac{12\times11}{6}=\frac{132}{6}=22\). Option A, 22, is correct because the common \(10!\) cancels and the remaining numerator is divided by 6. Option B, 24, is wrong because it does not correctly divide 132 by 6. Option C, 132, is the value before dividing by \(3!=6\), so it is incomplete. Option D, 220, is wrong and does not follow from the factorial simplification. A common mistake is to cancel \(10!\) but forget the additional denominator factor \(3!\).

Related tags

PermutationsCombinationsFactorialHard

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