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What is the value of \(\frac{3!+2!+1!}{0!}\)?\(\frac{3!+2!+1!}{0!}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 99
\(3!=6\), \(2!=2\), and \(1!=1\). Therefore, the numerator is \(6+2+1=9\). Also, \(0!=1\), so \(\frac{9}{1}=9\). Option 8 may result from incorrectly taking \(1!\) as 0. Exam tip: Always remember that both \(0!\) and \(1!\) are equal to 1.\(3!=6\), \(2!=2\) और \(1!=1\)। अतः अंश \(6+2+1=9\) है। साथ ही \(0!=1\), इसलिए \(\frac{9}{1}=9\)। विकल्प 8 तब मिल सकता है जब \(1!\) को गलती से 0 मान लिया जाए। परीक्षा टिप: \(0!=1\) और \(1!=1\) दोनों को हमेशा याद रखें।
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