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How many consecutive factors remain in (\frac{(n+4)!}{(n+1)!})?(\frac{(n+4)!}{(n+1)!}) में कितने लगातार गुणनखंड बचते हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
(\frac{(n+4)!}{(n+1)!}=(n+4)(n+3)(n+2)), so three factors remain. Reduce the numerator up to the denominator factorial.(\frac{(n+4)!}{(n+1)!}=(n+4)(n+3)(n+2)), इसलिए तीन गुणनखंड बचते हैं। हर के फैक्टोरियल तक अंश को घटाएं।
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