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What is the value of \(\frac{18!}{16!\cdot2}\)?

Answer and explanation

Correct answer: 153

Since \(18!=18\cdot17\cdot16!\), \(\frac{18!}{16!\cdot2}=\frac{18\cdot17\cdot16!}{16!\cdot2}=\frac{18\cdot17}{2}=9\cdot17=153\). Therefore, the correct answer is 153. The value 144 would result from using \(18\times16/2\), which incorrectly omits the factor 17. Exam tip: In factorial fractions, expand the larger factorial up to the smaller factorial and cancel common factors.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsClass 11 MathematicsMathematicsClass 11 Mcq

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