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What is the simplified form of \(\frac{(n+2)!+(n+1)!}{(n+1)!}\)?

Answer and explanation

Correct answer: \(n+3\)

Since \((n+2)!=(n+2)(n+1)!\), the numerator becomes \((n+2)(n+1)!+(n+1)!\). Taking \((n+1)!\) common gives \([(n+2)+1](n+1)!=(n+3)(n+1)!\). Dividing by \((n+1)!\) gives \(n+3\). Option \(n+2\) misses the contribution of the second term, \((n+1)!\). Exam tip: in factorial expressions, factor out the smaller factorial first.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsAlgebraic SimplificationClass 11 MathematicsMathematicsClass 11 Mcq

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