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If (n!=120), what is the value of ((n-2)!)?

Answer and explanation

Correct answer: 6

Since 120 = 5!, we get n = 5. Therefore, (n-2)! = (5-2)! = 3! = 3 × 2 × 1 = 6. The value 24 is 4!, which would arise if (n-1)! were asked. Exam tip: First identify n from the given factorial, then substitute it into the required factorial expression.

Related tags

Factorial NotationPermutations And CombinationsClass 11 MathematicsFactorial EvaluationMathematicsClass 11 Mcq

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