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What is the value of (\frac{9!}{6!\cdot3!})?

Answer and explanation

Correct answer: (84)

The direct answer is option C, 84. Since \(9!=9 imes8 imes7 imes6!\), we have \(\frac{9!}{6!}=9 imes8 imes7\). The expression becomes \(\frac{9 imes8 imes7}{3!}\). Because \(3!=3 imes2 imes1=6\), the value is \(\frac{9 imes8 imes7}{6}=84\). Option A, 56, is wrong because the numerator has not been divided correctly by 6. Option B, 72, is also an arithmetic error. Option C, 84, is correct. Option D, 96, does not follow from the factorial cancellation and is too large. A useful check is that 9×8×7 = 504 and 504 ÷ 6 = 84. Do not treat 3! as 3; it equals 6. Exam cue: cancel the larger common factorial first, then evaluate the small remaining factorial.

Related tags

Factorial NotationCombination FormClass 11

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