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What is the value of (8! − 7!) / 7!?

Answer and explanation

Correct answer: 7

The governing idea is factoring a common factorial. Because 8! = 8 × 7!, the numerator becomes 8 × 7! − 7! = (8−1) × 7! = 7 × 7!. Dividing by the denominator 7! gives (7 × 7!)/7! = 7. Therefore option B is correct. Another valid approach is to divide the two numerator terms separately: 8!/7! − 7!/7! = 8 − 1 = 7. A common error is to treat 8! − 7! as 1!, but factorial values cannot be subtracted by subtracting their arguments. Option C forgets the subtraction of 7!, option D has no valid factorial derivation, and option A is an incorrect reduction.

Related tags

Factorial NotationCommon FactorSubtractionClass 11Factorial NotationPermutations And CombinationsMathematicsClass 11 Mcq

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