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What is the value of \(\frac{10!}{8!\cdot2!}\)?

Answer and explanation

Correct answer: 45

Since \(10!=10\cdot9\cdot8!\), \(\frac{10!}{8!\cdot2!}=\frac{10\cdot9\cdot8!}{8!\cdot2}=\frac{90}{2}=45\). Hence, 45 is correct. The close distractor 90 results from forgetting to divide by \(2!\). Exam tip: expand the larger factorial only up to the smaller factorial, then cancel common factors.

Related tags

Factorial NotationPermutations And CombinationsFactorial SimplificationClass 11 MathematicsMathematicsClass 11 Mcq

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