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What is the value of (\frac{9!}{6!}-\frac{7!}{5!})?

Answer and explanation

Correct answer: (462)

The direct answer is option A, 462. Simplify the first quotient by cancelling 6!: \(\frac{9!}{6!}=\frac{9\times8\times7\times6!}{6!}=9\times8\times7=504\). For the second quotient, \(\frac{7!}{5!}=\frac{7\times6 imes5!}{5!}=7\times6=42\). The required subtraction is therefore \(504-42=462\). Option A, 462, is correct. Option B, 480, would come from an incorrect subtraction or from failing to reduce one quotient properly. Option C, 504, is only the first quotient and ignores the subtraction of 42. Option D, 546, does not follow from the required difference and may reflect adding rather than subtracting. The safe method is to cancel the smaller factorial first, calculate each quotient, and then apply the indicated minus sign. Exam cue: \(\frac{n!}{r!}\) leaves the factors from n down to r+1.

Related tags

Factorial NotationPermutations CombinationsClass 11Medium

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