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What is the value of \(\frac{11!}{9!,2!}\)?\(\frac{11!}{9!,2!}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 5555
Since \(11!=11\times10\times9!\) and \(2!=2\), \(\frac{11!}{9!,2!}=\frac{11\times10\times9!}{9!\times2}=\frac{110}{2}=55\). The value 66 is \(\binom{12}{2}\), so it does not apply here. Exam tip: In factorial fractions, first cancel the common factorial terms and then multiply the remaining factors.क्योंकि \(11!=11\times10\times9!\) और \(2!=2\) है, इसलिए \(\frac{11!}{9!,2!}=\frac{11\times10\times9!}{9!\times2}=\frac{110}{2}=55\)। विकल्प 66, \(\binom{12}{2}\) का मान है, इसलिए यहाँ सही नहीं है। परीक्षा टिप: फैक्टोरियल के भिन्न में पहले समान फैक्टोरियल पदों को काटें, फिर शेष गुणन करें।
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