What is the value of \(\frac{5!+3!}{4!}\)?

Correct answer: \(\frac{21}{4}\)

Here, \(5!=120\), \(3!=6\), and \(4!=24\). Therefore, \(\frac{5!+3!}{4!}=\frac{120+6}{24}=\frac{126}{24}=\frac{21}{4}\). Hence, \(\frac{21}{4}\) is the correct answer. Option 5 is only the value of \(\frac{5!}{4!}\); it ignores the \(3!\) term. Exam tip: evaluate each factorial first, then perform the addition and division.