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How many factors are present in (9!)?

Answer and explanation

Correct answer: 9

By definition, \(9! = 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\). There are 9 numbers being multiplied, so it has 9 factors in its factorial expansion. \(8\) would be the number of factors in \(8!\), not \(9!\). Exam tip: In the expanded form of \(n!\), there are \(n\) factors from \(n\) to 1.

Related tags

Factorial NotationPermutations And CombinationsClass 11MathematicsElementary FactorialsClass 11 Mcq

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