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How many factors from (6) to (1) are present in (6!)?

Answer and explanation

Correct answer: 6

By definition, \(6!=6\times5\times4\times3\times2\times1\). The product contains 6, 5, 4, 3, 2, and 1, so there are 6 factors in total. Choosing 5 would incorrectly omit the final factor, 1. Exam tip: \(n!\) contains \(n\) factors, from 1 to \(n\).

Related tags

Factorial NotationPermutations And CombinationsClass 11MathematicsBasic FactorialsClass 11 Mcq

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