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What is the value of \(\frac{3!+0!}{1!}\)?\(\frac{3!+0!}{1!}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 77
\(3!=3\times2\times1=6\), \(0!=1\), and \(1!=1\). Therefore, \(\frac{3!+0!}{1!}=\frac{6+1}{1}=7\). Option 6 would result from incorrectly taking \(0!\) as 0. Exam tip: always remember that \(0!=1\) and \(1!=1\).\(3!=3\times2\times1=6\), \(0!=1\) और \(1!=1\)। अतः \(\frac{3!+0!}{1!}=\frac{6+1}{1}=7\)। विकल्प 6 तब मिलता यदि \(0!\) को गलती से 0 मान लिया जाए। परीक्षा टिप: \(0!=1\) और \(1!=1\) हमेशा याद रखें।
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