What is the value of \(\frac{4!+2!}{2!}\)?

Correct answer: 13

Here, \(4!=4\times3\times2\times1=24\) and \(2!=2\times1=2\). Therefore, \(\frac{4!+2!}{2!}=\frac{24+2}{2}=\frac{26}{2}=13\). Hence, 13 is the correct option. Option 12 can result from incorrectly evaluating \(2!\) or mishandling the addition in the numerator. Exam tip: evaluate each factorial first, add the terms in the numerator, and then divide.