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Class 11MathematicsPermutations and CombinationsFactorial notationEasy
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How many factors are written in (7!)?

Answer and explanation

Correct answer: (7)

(7!=7\times6\times5\times4\times3\times2\times1), which has (7) factors. In (n!), factors run from (n) down to (1).

Related tags

Factorial NotationPermutations CombinationsClass 11EasyFactorial NotationPermutations And CombinationsMathematicsClass 11 Mcq
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10 more MCQs
  1. 1What is the value of 5!?
  2. 2What is the value of 0!?
  3. 3What is the value of (1!+3!)?
  4. 4What is the simplified value of \(\frac{6!}{4!}\)?
  5. 5What is the value of (\frac{7!}{5!,2!})?
  6. 6Which form can represent (n!)?
  7. 7What is the value of (4!+2!)?
  8. 8What is the value of 8!/7!?
  9. 9How can (9\times8\times7) be written in factorial form?
  10. 10For a positive integer \(n\), which of the following statements gives the correct definition of \(n!\)?
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