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What is the least (n) for which (n!) is divisible by (343)?

Answer and explanation

Correct answer: 21

Since 343 = 7^3, n! must contain at least three factors of 7. In 21!, the numbers 7, 14, and 21 contribute three factors of 7, so 7^3 divides 21!. In contrast, 20! contains only two factors of 7, from 7 and 14, so it is not divisible by 343. Exam tip: For a prime power p^k, count the factors of p present in n!.

Related tags

Factorial NotationDivisibilityPrime PowersLegendre FormulaPermutations And CombinationsMathematicsClass 11 Mcq

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