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Which value is equal to \(\frac{25!}{23!}\)?

Answer and explanation

Correct answer: 600

We have \(25!=25\times24\times23!\). Therefore, \(\frac{25!}{23!}=\frac{25\times24\times23!}{23!}=25\times24=600\). Hence, option B is correct. In contrast, \(625=25\times25\), whereas the required consecutive factors are \(25\) and \(24\). Exam tip: In \(\frac{n!}{(n-r)!}\), multiply only the consecutive factors that remain after cancellation.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsCancellationGrade 11MathematicsClass 11 Mcq

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