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What is the value of \(\frac{14!+13!}{12!}\)?

Answer and explanation

Correct answer: 195

Since \(14!=14\times13!\), we get \(14!+13!=14\times13!+13!=13!(14+1)=15\times13!\). As \(13!=13\times12!\), \(\frac{15\times13!}{12!}=15\times13=195\). Hence, option B is correct. \(210\) may result from incorrectly treating the expression as \(14\times15\). Exam tip: for sums of factorials, first factor out the smaller common factorial.

Related tags

Factorial NotationFactorial SimplificationPermutations And CombinationsAlgebraic ManipulationClass 11 MathematicsMathematicsClass 11 Mcq

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