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Class 11MathematicsPermutations and CombinationsCombinationsExpert
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(9) identical balls are to be placed into (3) distinct boxes so that no box has more than (4) balls. How many ways are possible?

Answer and explanation

Correct answer: (10)

Total distributions are (^{11}C_{2}=55). Subtract (3\times{}^{6}C_{2}=45) cases where one box has at least (5) balls, giving (10).

Related tags

Bounded-DistributionInclusion-ExclusionExpertCombinationsPermutations And CombinationsMathematicsClass 11 Mcq
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